Question:

The gradient of the tangent to the curve y=tan-1(sinx) at x=0 is:

Answer:

If f(x)=tan-1(sinx) f'(x)=1sin2x×cosx Now f'(x)=cos(0)1+sin2(0) =11+0 =1

Inverse & Further Trigonometric
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Inverse & Further Trigonometric
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